In an ammeter, 10% of main current is passing through the galvanometer. If the resistance of the galvanometer is G, then the shunt resistance is
9G
G9
90G
G90
We have, Ig=10% of I=0.1 I We know, the shunt resistance is given by: S=GIgI−Ig=0.1IGI−0.1I=G9