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In an ammeter...

Question

In an ammeter there are 19 additional marks between $0 A$ to $1 A$ marks. The least count of the ammeter is :

A

1 / 19

A

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B

1 / 20

A

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C

1 / 21

A

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D

1

A

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Solution

The correct option is C $1 / 20$ $A$
Total number of divisions is $20$ .
Least count (L.C.) of an Ammeter $= \frac{1 A}{T o t a l n u m b e r o f d i v i s i o n s} = \frac{1}{20} A$

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