In an AP, given l $= 28$ , S $= 144$ , and there are total $9$ terms. Find a.

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Solution

$l = 28, s = 144, n = 9$
$s = \frac{n}{2} (a + l)$
$144 = \frac{9}{2} (a + 28)$
$\frac{288}{9} = a + 28$
$32 = a + 28$
$a = 4$

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In an AP, given l=28, S=144, and there are total 9 terms. Find a.

l=28,s=144,n=9s=n2(a+l)144=92(a+28)2889=a+2832=a+28a=4

In an AP, given l $= 28$ , S $= 144$ , and there are total $9$ terms. Find a.

$l = 28, s = 144, n = 9$
$s = \frac{n}{2} (a + l)$
$144 = \frac{9}{2} (a + 28)$
$\frac{288}{9} = a + 28$
$32 = a + 28$
$a = 4$