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Question

In an AP, if Sn=3n2+5n and ak=164, find the value of k.

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Solution

Sn=3n2+5n
S1=a=3+5=8
and S2=a1+a2=3×22+5×2=22
a+a+d=222a+d=22
d=222a=2216=6
Now ak=164
a+(k1)d=164
8+(k1)6=164
(k1)6=156
k1=26k=27

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