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Mathematics

Arithmetic Progression

In an AP. S p...

Question

In an AP. S_p = q, S_q = p and S_r denotes the sum of first r terms. Then, S_p_+q is equal to

(a) 0

(b) −(p + q)

(c) p + q

(d) pq

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Solution

In the given problem, we are given and

We need to find

Now, as we know,

So,

Similarly,

Subtracting (2) from (1), we get

Now,

Thus,

Hence, the correct option is (b).

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Similar questions

Q. In an A.P.,

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and

S_{q} = p

, where

S_{r}

denotes the sum of the first

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S_{p + q}

Q. In an

A . P

S_{p} = q, S_{q} = p

. Where

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S_{p + q} =

Q. In an A.P.,

s_{p} = q, s_{q} = p a n d s_{r}

denotes the sum of the first r terms. Then

S_{p + q}

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Q. If the sum of p terms of an A.P. is q and the sum of q terms is p, then the sum of p + q terms will be
(a) 0
(b) p − q
(c) p + q
(d) − (p + q)

If a and d are the first term and the common difference of an AP, $S_{n}$ denotes the sum to n terms of an AP. If $S_{n} = P n + Q n^{2}$ , what are P and Q?

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In an AP. Sp = q, Sq = p and Sr denotes the sum of first r terms. Then, Sp+q is equal to (a) 0 (b) −(p + q) (c) p + q (d) pq

In the given problem, we are given and We need to find Now, as we know, So, Similarly, Subtracting (2) from (1), we get Now, Thus, Hence, the correct option is (b).

In an AP. S_p = q, S_q = p and S_r denotes the sum of first r terms. Then, S_p_+q is equal to

(a) 0

(b) −(p + q)

(c) p + q

(d) pq

In the given problem, we are given and

We need to find

Now, as we know,

So,

Similarly,

Subtracting (2) from (1), we get

Now,

Thus,

Hence, the correct option is (b).