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Question

In an AP, tn denotes nth terms and Sn denotes sum of n terms. If tm=1n and tn=1m, find Smn.

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Solution

Given,

tm=a+(m1)d=1n.....(1)

tn=a+(n1)d=1m........(2)

1n1m=a+(m1)da(n1)d

mnmn=a+mddand+d

mnmn=(mn)d

d=1mn

From (1)

a+(m1)d=1n

a+(m1)1mn=1n

an+(m1)1m=1

a=1mn

Smn=mn2[2a(mn1)d]

=mn2[2(1mn+(mn1)mn2)]

=mn2[2mn+mn1mn]

=mn2mn[2+mn1]

=12[mn+1]

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