In an AP, the 6th term is $52$ and the 11th term is $112$ . Then, the common difference is equal to

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Solution

The correct option is D $12$
$n^{t h}$ term of AP $= 52$
$\Rightarrow$ $a + 5 d = 52... (i)$
And 11th term of AP $= 12$
$\Rightarrow$ $a + 10 d = 112..... (i i)$
Subtracting Eq(i) from Eq.(ii) we get
$5 d = 60$
$∴$ $d = \frac{60}{5} = 12$

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In an AP, the 6th term is 52 and the 11th term is 112. Then, the common difference is equal to

The correct option is D 12nth term of AP=52⇒ a+5d=52...(i)And 11th term of AP=12⇒ a+10d=112.....(ii)Subtracting Eq(i) from Eq.(ii) we get5d=60∴ d=605=12

In an AP, the 6th term is $52$ and the 11th term is $112$ . Then, the common difference is equal to

The correct option is D $12$
$n^{t h}$ term of AP $= 52$
$\Rightarrow$ $a + 5 d = 52... (i)$
And 11th term of AP $= 12$
$\Rightarrow$ $a + 10 d = 112..... (i i)$
Subtracting Eq(i) from Eq.(ii) we get
$5 d = 60$
$∴$ $d = \frac{60}{5} = 12$