In an AP, The ratio of 7th term to 3th term is in ratio 2:1 . Find the ratio of 11th term to 8th term.
Solution: Option (b)
Let the first term be a, common difference be d.
t7=a+6d, t3=a+2d, t7=2t3⇒a+6d=2(a+2d)⇒a=2d.
t11=a+10d=2d+10=12d
t8=a+7d=2d+7d=9d
So, required ratio =12d:9d=4:3