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Question

In an AP, The ratio of 7th term to 3rd term is in ratio 2:1. Find the ratio of 11th term to 8th term.

A
3: 4
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B
4: 3
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C
2: 5
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D
5: 2
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E
2: 1
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Solution

The correct option is B 4: 3

Solution: Option (b)

Let the first term be a, common difference be d.

t7 = a + 6d, t3 = a + 2d, t7 = 2t3 => a + 6d = 2(a + 2d) => a = 2d

t11 = a + 10d = 2d + 10 = 12d

t8 = a + 7d = 2d + 7d = 9d

So, required ratio = 12d: 9d = 4: 3


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