In an AP, The ratio of 7th term to 3rd term is in ratio 2:1. Find the ratio of 11th term to 8th term.
Solution: Option (b)
Let the first term be a, common difference be d.
t7 = a + 6d, t3 = a + 2d, t7 = 2t3 => a + 6d = 2(a + 2d) => a = 2d
t11 = a + 10d = 2d + 10 = 12d
t8 = a + 7d = 2d + 7d = 9d
So, required ratio = 12d: 9d = 4: 3