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Sequence

In an AP ther...

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In an AP there are 25 terms, such that a2+a4+a6+a24+a22+a20=42 Find the sum of n terms

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a_{1}, a_{2}, a_{3}, \dots

are terms of AP such that

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

, then the sum of first

24

a_{1}, a_{2}, . . . . . ., a_{24}

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

then the sum of 24 terms of this AP is.

a_{1}, a_{2}, a_{3}, . . . . . . . . .

A . P .

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

, then the sum of first

24

A . P

Q. Assertion :Statement-1 If

a_{1}, a_{2}, a_{3}, . . . . . . . . . ., a_{24}

are In A. P. such that

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

a_{1} + a_{2} + a_{3} + . . . . . . + a_{23} + a_{24} = 900

because Reason: Statement-2 In any A.P. sum of the terms equidistant from begining and end is constant and is equal to
the sum of the first and the last term,

Q. What is the sum of the first 24 terms of the AP

a_{1}, a_{2}, a_{3}, \dots \dots

, if it is known that

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

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