In an AP, where the first term is 7 and the common difference is 4, ___term of the AP will be five times the first term. (Enter a number)

Open in App

Solution

First term $a$ = 7 and common difference $d$ = 4
Given, $a_{n}$ = $5 a$
$5 a = 5 \times 7 = 35$
Now, $n^{t h}$ term of the AP, $a_{n} = a + (n - 1) d$
$a_{n} = 7 + (n - 1) 4$
$35 = 7 + (n - 1) 4$
$n - 1 = 7$
$n = 8$
$∴$ $8^{t h}$ term of the AP is five times the first term.

Suggest Corrections

Similar questions

Q. In an AP, where the first term is 7 and the common difference is 4, ___term of the AP will be five times the first term. (Enter number only)

In an AP, the first term is 7 and the common difference is 4. Which term of the AP will be five times the first term?

In an AP, where the first term is 7 and the common difference is 4, ___ term of the AP will be five times the first term.
Represent this situation in the form of an equation, where $a$ = first term, $a_{n}$ = $n^{t h}$ term and $d$ is the common difference.

Q. In an AP, where the first term is 7 and the common difference is 4, ___ term of the AP will be five times the first term.
Represent this situation in the form of an equation, where

a

= first term,

a_{n}

n^{t h}

term and

d

is the common difference.

Q. In an AP, where the first term is 7 and the common difference is 4, find the 5th term.

Join BYJU'S Learning Program

In an AP, where the first term is 7 and the common difference is 4, ___term of the AP will be five times the first term. (Enter a number)

First term a = 7 and common difference d = 4 Given, an = 5a 5a=5×7=35 Now, nth term of the AP, an=a+(n−1)d an=7+(n−1)4 35=7+(n−1)4 n−1=7 n=8 ∴ 8th term of the AP is five times the first term.

First term $a$ = 7 and common difference $d$ = 4
Given, $a_{n}$ = $5 a$
$5 a = 5 \times 7 = 35$
Now, $n^{t h}$ term of the AP, $a_{n} = a + (n - 1) d$
$a_{n} = 7 + (n - 1) 4$
$35 = 7 + (n - 1) 4$
$n - 1 = 7$
$n = 8$
$∴$ $8^{t h}$ term of the AP is five times the first term.