In an apparatus, electric field was found to oscillate with an amplitude of $18 V / m$ . The magnitude of the oscillating magnetic field will be

4 \times 10^{- 6} T

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6 \times 10^{- 8} T

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9 \times 10^{- 9} T

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11 \times 10^{- 11} T

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Solution

The correct option is B $6 \times 10^{- 8} T$
Here, $E_{0} = 18 V / m$ .
$B_{0} = \frac{E_{0}}{c} = \frac{18}{3 \times 10^{8}} = 6 \times 10^{- 8} T$

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In an apparatus, electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be

The correct option is B 6×10−8THere, E0=18V/m.B0=E0c=183×108=6×10−8T

In an apparatus, electric field was found to oscillate with an amplitude of $18 V / m$ . The magnitude of the oscillating magnetic field will be

The correct option is B $6 \times 10^{- 8} T$
Here, $E_{0} = 18 V / m$ .
$B_{0} = \frac{E_{0}}{c} = \frac{18}{3 \times 10^{8}} = 6 \times 10^{- 8} T$