In an archery practice an arrow was released from the bow with velocity 20m/s. it strikes the board 15m ahead and stops.
find at what rate the arrow was accelerated

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Solution

Dear Student,

$u = 20 m / s s = 15 m v = 0 v^{2} - u^{2} = 2 a s 0 - {(20)}^{2} = 2 \times 15 \times a a = \frac{- 400}{30} = - 13.33 m / s^{2}$

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In an archery practice an arrow was released from the bow with velocity 20m/s. it strikes the board 15m ahead and stops. find at what rate the arrow was accelerated

Dear Student, u=20 m/ss=15 mv=0v2-u2=2as0-202=2×15×aa=-40030=-13.33 m/s2

In an archery practice an arrow was released from the bow with velocity 20m/s. it strikes the board 15m ahead and stops.
find at what rate the arrow was accelerated

Dear Student,

$u = 20 m / s s = 15 m v = 0 v^{2} - u^{2} = 2 a s 0 - {(20)}^{2} = 2 \times 15 \times a a = \frac{- 400}{30} = - 13.33 m / s^{2}$