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Solving Equations x+a = b and x-a = b by Rearranging Terms

In an arithem...

Question

In an arithematic sequence 2nd term is 8. Find the sum of the 1st term and 3rd term

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Solution

Let the first term is a
The second term is a + d
The third term is a + 2d
Sum of first and third term = a + a + 2d
= 2 (a + d)
= 2 $\times$ 2nd term
= 2 $\times$ 8 = 16

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Solving Equations x+a = b and x-a = b by Rearranging Terms

Standard VI Mathematics

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