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Question

In an arithmetic progression, the fourth term is 8 and the sum of 12 terms is 156. Find the value of 'p' if the p th term is 1000.

A
200
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B
500
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C
300
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D
100
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Solution

The correct option is B 500
Let first term be a and common difference be d
a+3d=8 .....(1)
122[2a+(121)d]=156
2a+11d=26 .....(2)
From eq(1) and eq(2):
a=2 and d=2
Now,
pth term =2+(p1)2=1000
(p1)2=998
(p1)=499
p=500
(Ans = B)

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