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Question

In an atom, an electron is moving with the speed of 600 m/s have an accuracy of 0.005%. The minimum uncertainity with which the position of the electron can be located is:
h=6.6×1034 Js,mass of electron,em=9.1×1031 kg


A
5.10×103 m
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B
1.92×103 m
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C
3.84×103 m
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D
1.52×103 m
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Solution

The correct option is B 1.92×103 m
Given:
Speed of electron = 600 m/s
Accuracy of speed = 0.005%
Uncertainity in speed (Δv)=600×0.005100=0.03 m/s
Let uncertainity in the position be Δx.
According to Heisenberg's uncertainity principle:
mΔvΔxh4π
Minimum Δx=h4πmΔv=6.6 × 10344 × 3.14 × 9.1 × 1031 × 0.03=1.92 × 103 m

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