In an atom, for how many electrons the quantum numbers will be $n = 3, l = 2, m = + 2, s = + 1 / 2$ ?

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Solution

The correct option is D 1
In an atom, for only one electron the quantum numbers will be $n = 3, l = 2, m = + 2, s = + 1 / 2$ . This is in accordance with Pauli's exclusion principle which states that " No two electrons of an atom can have the same set of all the four quantum numbers".

Hence, the correct option is $D$

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Similar questions

n = 3, l = 2, m = + 2, s = + 1 / 2

n = 4, m_{s} = - 1 / 2

n = 3, l = 0

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m = - \frac{1}{2}$
(b) n = 3, l = 0

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

n = 4, m_{s} = - \frac{1}{2}

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