In an atom, the total number of electrons having quantum numbers $n = 3, | m_{l} | = 0$ and $m_{s} = - \frac{1}{2}$ is :

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Solution

The correct option is C 3
Given,
$| m_{l} | = 0$ means $m_{l}$ is zero
Since n = 3, the possible values of ` $l$ ' are 0,1 and 2 .
The orbitals in shell 3 with m = 0 are, 3s orbital,one of the 3p orbitals and also one of the 3d orbitals. So total of 3 orbitals.

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Similar questions

n = 4,

m_{l}

m_{s}

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

In an atom, the total number of electrons having quantum number
$n = 4, | m_{l} | = 1 a n d m_{s} = - \frac{1}{2} i s$ ___

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

n = 4, m_{s} = - 1 / 2

n = 3, l = 0

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