In an atom, the total number of electrons having quantum numbers $n = 4$ , $| m_{l} | = 1$ and $m_{s} = - \frac{1}{2}$ is :

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Solution

The correct option is B 6
quantum numbers $n = 4, m_{l}, m_{s} = \frac{- 1}{2}$
$m_{l} = 1, - 1$
$[\begin{matrix} 4 s & 4 p & 4 d & 4 f l = 0 & l = 1 & l = 2 & l = 3 \end{matrix}]$

$4 p \to l = 1 \to m_{l} = - 1, 0, 1 \Rightarrow 2 e^{- s}$
$4 d \to l = 2 \to m_{l} = - 2, - 1, 0, 1, 2 \Rightarrow 2 e^{- s}$
$4 f \to l = 3 \to m_{l} = - 3, - 2, - 1, 0, 1, 2, 3 \Rightarrow 2 e^{- s}$
total number of electrons $= (3) (2) = 6$ electrons

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