In an atom, the total number of electrons having quantum numbers $n = 4, | m_{l} | = 1$ and $m_{s} = \frac{- 1}{2}$ are___.

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Solution

$n = 4, l = 0, 1, 2, 3$

For $l = 0 \Rightarrow | m_{l} | \neq 1 (m_{l} = 0)$

For $l = 1 \Rightarrow m_{l} = - 1, 0, + 1 \Rightarrow 2$ electrons with same spin. $(f o r | m_{l} | = 1)$

For $l = 2 \Rightarrow m_{l} = - 2, - 1, 0, + 1, + 2 \Rightarrow 2$ electrons with same spin for $| m_{l} | = 1$

For $l = 3 \Rightarrow m_{l} = - 3, - 2, - 1, 0 + 1 + 2, + 3 \Rightarrow 2$ electrons with same spin. $| m_{l} | = 1$

Total electons = 6

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Similar questions

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

n = 4, | m_{l} | = 1

m_{s} = - 1 / 2

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

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