In an atom, the total number of electrons having quantum numbers $n = 4, | m_{l} | = 1$ and $m_{s} = - 1 / 2$ are:

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Solution

$n = 4$
$l = 0, 1, 2, 3$
$| m_{l} | = 1 \Rightarrow \pm 1$
$m_{s} = - \frac{1}{2}$
For
$l = 0, m_{l} = 0$
$l = 1, m_{l} = - 1, 0, + 1$
$l = 2, m_{l} = - 2, - 1, 0, + 1, + 2$
$l = 3, m_{l} = - 3, - 2, - 1, 0, + 1, + 2, + 3$
So, six electrons can have $| m_{l} | = 1$ & $m_{s} = - \frac{1}{2}$ two each in p, d and f subshell.

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Similar questions

In an atom, the total number of electrons having quantum numbers $n = 4, | m_{l} | = 1$ and $m_{s} = \frac{- 1}{2}$ are___.

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

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