Question

In an atom, which has $2K,8L,$ $18M,$ and $2N$ electrons in the ground state. The total number electron having magnetic quantum number, $m=0$ is:

• A. $6$
• B. $10$
• C. $7$
• D. $14$

Answer 1

Answer: (D)

$14$

Given,

Electronic configuration is $\underset{K}{\underset{}{1s^2}}\underset{L}{\underset{}{2s^{2}2p^6}}\underset{M}{\underset{}{3s^{2}3p^6}}\underset{N}{\underset{}{4s^2}}\underset{M}{\underset{}{3d^{10}}}$

$1s^2\to$ As refer to IMAGE $01\Rightarrow 2$ electrons

$2s^2\to$ As refer to IMAGE $02\Rightarrow 2$ electrons

$2p^6\to$ As refer to IMAGE $03\Rightarrow 2$ electrons

$3s^2\to$ As refer to IMAGE $04\Rightarrow 2$ electrons

$3p^6\to$ As refer to IMAGE $05\Rightarrow 2$ electrons

$4s^2\to$ As refer to IMAGE $06\Rightarrow 2$ electrons

$3d^{10}\to$ As refer to IMAGE $07\Rightarrow 2$ electrons

With $m=0$ there are $14$ electrons.