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Question
In an attempted determination of the solubility product constant of TI2S the solubility of this compound in pure CO2− free water was determined as 6.3 × 10−6 mol/L. Assume that the dissolved sulfidehydrolyzes almost completely to HS− and that the further hydrolysis to H2S can be neglected. What is the computed Ksp ?
In an attempted determination of the solubility product constant of TI2S the solubility of this compound in pure CO2− free water was determined as 6.3 × 10−6 mol/L. Assume that the dissolved sulfidehydrolyzes almost completely to HS− and that the further hydrolysis to H2S can be neglected. What is the computed Ksp ?
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Solution
The correct option is C
LT2S ⇌ 2Tl+ + S2−, Ksp = [Tl+]2[S2−]
S2− + H2O ⇌ HS− + OH−
Kh = KwK2 = 1.0 × 10−141.0 × 10−14 = 1.0
[T+] = 2(6.3 × 10−6)[HS−] = 6.3 × 10−6
Kh = (6.3 × 10−6)2[S2−] = 1.0
[S2−] = (6.3 × 10−6)2
Ksp = (6.3 × 10−6)2[2(6.3 × 10−6)]2
= 6.3 × 10−21
LT2S ⇌ 2Tl+ + S2−, Ksp = [Tl+]2[S2−]
S2− + H2O ⇌ HS− + OH−
Kh = KwK2 = 1.0 × 10−141.0 × 10−14 = 1.0
[T+] = 2(6.3 × 10−6)[HS−] = 6.3 × 10−6
Kh = (6.3 × 10−6)2[S2−] = 1.0
[S2−] = (6.3 × 10−6)2
Ksp = (6.3 × 10−6)2[2(6.3 × 10−6)]2
= 6.3 × 10−21
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