In an auditorium, 600 tickets were sold. The total sale of tickets was rupees 4250. If the tickets denominations were ₹ 2.5, ₹ 5.0 and ₹ 10.0. how many of each denominations were sold ?

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Solution

Let 1st ticket =X
2nd ticket =Y
3rd ticket=Z
according to given condition
X+Y+Z=600........1)
2.5X+5Y+10Z=4250.......2)
there are 2 equations and 3 variables
it is not possible to solve
complete the question
here is a similiar one

In a cinema halls 300 tickets were sold.the total sale of tickets were rs 1250.of the tickets were of two denominations rs 2.50 and rs.5.00

Let the number of Rs 2.50 tickets be x and 5.00 tickets be y.
As per the question, x+y = 300 (eq.1)
Also, 2.5x + 5.0x = 1250
2.5 ( x+2y) = 1250
x+ 2y = 1250/2.5
x+ 2y = 500 (eq.2)

(eq 2) - (eq 1)
x+2y - x-y = 500-300
y = 200

Substitute y in eq 1
x+200 = 300
x = 300-200
x = 100

Therefore, there are 100 Rs 2.5 tickets and 200 Rs 5.00 tickets.

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