The correct option is C 910 Required probabilty = 1 P(hindi) =1 10100=90100=910 ...

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Standard XII

Mathematics

Axiomatic Approach

In an country...

Question

In an country 50% speaks english, 20% french, 10% german, 10% hindi and remaining 10% speaks korian language. Person is choosen at random, what is the probability that he does not speak hindi?

\frac{1}{10}

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\frac{9}{10}

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\frac{1}{2}

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\frac{1}{5}

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Solution

The correct option is C $\frac{9}{10}$
Required probabilty $= 1 -$ P(hindi) $= 1 - \frac{10}{100} = \frac{90}{100} = \frac{9}{10}$

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In an country 50% speaks english, 20% french, 10% german, 10% hindi and remaining 10% speaks korian language. Person is choosen at random, what is the probability that he does not speak hindi?

The correct option is C 910Required probabilty =1−P(hindi)=1−10100=90100=910

The correct option is C $\frac{9}{10}$
Required probabilty $= 1 -$ P(hindi) $= 1 - \frac{10}{100} = \frac{90}{100} = \frac{9}{10}$