Question

In an election $3$ persons are to be elected from $6$ candidates. A voter can cast any number of votes but not more than the candidates to be elected. In how many ways can he cast his vote?

• A. $41$
• B. $20$
• C. $15$
• D. $6$

Answer 1

The correct option is A $41$

Now a person can vote $1$ or $4$ or $3$ times. If he vote $4$ times then no. of ways ${=}^6{C}_1=6$

If he votes for $2$ times; then no. of ways ${=}^6{C}_2=15$

If he votes for $3$ times, then no. of ways ${=}^6{C}_3=20$

Total ways $=6+15+20=41$