In an election there are 8 candidates, out of which 5 are to be chosen. If a voter can vote at least one candidate but not more than the number to be choosen, then in how many ways can a voter vote ?

216

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114

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218

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144

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Solution

The correct option is C 218
Total number of candidates are 8 and we have to select 5 candidates.
The total number of ways a voter can vote
$=^{8} C_{1} +^{8} C_{2} +^{8} C_{3} +^{8} C_{4} +^{8} C_{5}$
$= 8 + 28 + 56 + 70 + 56 = 218$

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In an election there are 8 candidates, out of which 5 are to be chosen. If a voter can vote at least one candidate but not more than the number to be choosen, then in how many ways can a voter vote ?

The correct option is C 218Total number of candidates are 8 and we have to select 5 candidates.The total number of ways a voter can vote=8C1+8C2+8C3+8C4+8C5=8+28+56+70+56=218

The correct option is C 218
Total number of candidates are 8 and we have to select 5 candidates.
The total number of ways a voter can vote
$=^{8} C_{1} +^{8} C_{2} +^{8} C_{3} +^{8} C_{4} +^{8} C_{5}$
$= 8 + 28 + 56 + 70 + 56 = 218$