Question

In an election there were two candidates $A$ and $B$$.$ The total number of voters in this constituency were $60,000$ and $80\%$ of the total votes were polled$.$ If $60\%$ of the polled votes were cast in favour of $A$$,$ How many votes were received by $B?$

Answer 1

Step $1:$ To find the number of votes were received by $B$

It is given that total number of votes $=60,000$

Total number of polled votes $=80\%$ of $60,000$

$=$$\frac{80}{100}\times 60,000$

$=80\times 600$

$=48000$

Step $2:$ Now find $60\%$ of $48,000$

$60\%$ of $48,000$

$=\frac{60}{100}\times 48000$

$=60\times 480$

$=28,800$

Number of votes received by $A=$$28,800$

Number of votes received by $B$ $=48000-28800$

$=19200$

Hence, the number of votes received by $B$ were $19,200$