In an election two candidate $P$ and $Q$ consented. $P$ got $70 %$ of the votes. The total votes poled were $75000$ . How many votes did each get?

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Solution

Total votes poled $= 75000$

If $P$ gets $70$ % of the votes. Then $Q$ gets $30$ % of the votes.

Number of votes $P$ gets $= 70$ % of $75000 = \frac{70}{100} \times 75000 = 52, 500$

Number of votes $Q$ gets $= 30$ % of $75000 = \frac{30}{100} \times 75000 = 22, 500$

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In an election two candidate P and Q consented. P got 70% of the votes. The total votes poled were 75000. How many votes did each get?

Total votes poled =75000If P gets 70% of the votes. Then Q gets 30% of the votes.Number of votes P gets =70 % of 75000=70100×75000=52,500Number of votes Q gets =30 % of 75000=30100×75000=22,500

In an election two candidate $P$ and $Q$ consented. $P$ got $70 %$ of the votes. The total votes poled were $75000$ . How many votes did each get?

Total votes poled $= 75000$

If $P$ gets $70$ % of the votes. Then $Q$ gets $30$ % of the votes.

Number of votes $P$ gets $= 70$ % of $75000 = \frac{70}{100} \times 75000 = 52, 500$

Number of votes $Q$ gets $= 30$ % of $75000 = \frac{30}{100} \times 75000 = 22, 500$