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Question

In an electric circuit, two resistors of 2Ω and 4Ω are connected in series with a 12 V battery.
Find out the voltage across the 4Ω resistor ?

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A
3 V
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B
4 V
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C
6 V
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D
8 V
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E
12 V
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Solution

The correct option is D 8 V
Given : R1=2Ω R2=4Ω
Total resistance of the circuit R=R1+R2=2+4=6Ω
Voltage drop across 4Ω, V4=R2RV=46×12=8 volts

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