Question

In an electric field shown in figure three equipotential surfaces are shown. If function of electric field is $2x^2\frac{V}{m}$, and given that $V_1-V_2=V_2-V_3$ then we have

• A. $x_1=x_2$
• B. $x_1>x_2$
• C. $x_2>x_1$
• D. data insufficient

Answer 1

The correct option is B

$x_1>x_2$

$E=2X^2\frac{v}{m}HereE\uparrow asx\uparrow Since{v}_1-v_2=v_2-v_{3}andV=E△XSo{x}_1>x_2$