In an electrical circuit, two resistors of 2Ω and 4Ω respectively are connected in series to a 6V battery. The heat dissipated by the 4 Ω resistor in 5s will be:
A
5J
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B
10J
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C
20J
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D
30J
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Solution
The correct option is C20J The equivalent resistance for resistors connected in series, Req=R1+R2=2+4=6Ω
Voltage, V=6V
Current, I=VR=66=1A
The electric current flowing through the resistors is the same.
The heat dissipated by the 4Ω resistor in 5s is given by, =I2Rt=(1)2×4×5=20J