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Standard IX

Physics

Resistance

In an electri...

Question

In an electrical circuit two resistors of 2ohm and 4ohm respectively are connected in series to a 6V battery. Find the heat dissipated by the 4ohm resistor.

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Solution

Dear Student,
Net resistance of the circuit, R = 2 ohm + 4 ohm = 6 ohm.
Voltage applied, V = 6 V
Current in the circuit, I = V/R = 1 A
Heat dissipated by the 4 ohm resistance per unit time, $P = I^{2} R = 1^{2} \times 4 = 4 W a t t s$
Regards

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In an electrical circuit two resistors of 2ohm and 4ohm respectively are connected in series to a 6V battery. Find the heat dissipated by the 4ohm resistor.

Dear Student, Net resistance of the circuit, R = 2 ohm + 4 ohm = 6 ohm. Voltage applied, V = 6 V Current in the circuit, I = V/R = 1 A Heat dissipated by the 4 ohm resistance per unit time, P = I2R =12×4 = 4 Watts Regards

Dear Student,
Net resistance of the circuit, R = 2 ohm + 4 ohm = 6 ohm.
Voltage applied, V = 6 V
Current in the circuit, I = V/R = 1 A
Heat dissipated by the 4 ohm resistance per unit time, $P = I^{2} R = 1^{2} \times 4 = 4 W a t t s$
Regards