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Question

In an electroplating experiment, m g of silver is deposited when 4 A of current flows for 2 minutes. The amount in g of silver deposited by 6 A of current for 40 seconds will be

A
4m
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B
2m
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C
m2
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D
m4
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Solution

The correct option is C m2
According to Faraday's law of electrolysis, the mass deposited is:
m=zIt,
where z= electrochemical equivalent of substance.
Here, in both cases, substance is silver.
So z will be constant.
Now, m1=z×4×(2×60)=480z
and m2=z×6×40=240z
Thus, m2m1=240z480z=12
or, m2=m12=m2

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