In an Ellipse distance between the foci is 6 and the length of minor axis is 8. Its eccentricity is
2/5
4/5
3/5
1/3
2ae=6,2b=8⇒b=4
b2=a2−a2e2⇒16=a2−9⇒a2=25
e=√1−1625=√925=35
If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8, then the eccentricity Is