In an ellipse the length of major axis is $10$ and the distance between the foci is $8$ . Then the length of minor axis is:

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $6$
Given that length of major axis $= 2 a = 10$ and distance between the foci $= 2 a e = 8$
$e = \frac{4}{5}$
Now, $2 b = 2 a \sqrt{(1 - e^{2})} = 10 \sqrt{1 - \frac{16}{25}} = 6$

Suggest Corrections

Similar questions

10

e = \frac{1}{\sqrt{2}}

In an Ellipse distance between the foci is 6 and the length of minor axis is 8. Its eccentricity is

6

8

If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8, then the eccentricity Is

6

8

Join BYJU'S Learning Program