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Question
In an embryo with a complete deficiency of pyruvate kinase, how many net moles of ATP are generated during the conversion of 1 mole of glucose to 1 mole of pyruvate?
In an embryo with a complete deficiency of pyruvate kinase, how many net moles of ATP are generated during the conversion of 1 mole of glucose to 1 mole of pyruvate?
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Solution
The correct option is A 0.0
Normally, 1 mole of ATP each is used to convert 1 mole of glucose to 1 mole of glucose-6-phosphate and to convert 1 mole of fructose-6-phosphate to bisphosphate.
Two triose phosphates are produced by cleavage of fructose-1,6-bisphosphate. As the two triose phosphates are converted to pyruvate, four ATPs are generated; two by phosphoglycerate kinase and two by pyruvate kinase.
Net, two ATPs are produced. If pyruvate kinase is completely deficient, two less ATPs will be produced, and thus the net ATP production will be zero. It is unlikely that the embryo would survive with a complete deficiency of this enzyme.
Normally, 1 mole of ATP each is used to convert 1 mole of glucose to 1 mole of glucose-6-phosphate and to convert 1 mole of fructose-6-phosphate to bisphosphate.
Two triose phosphates are produced by cleavage of fructose-1,6-bisphosphate. As the two triose phosphates are converted to pyruvate, four ATPs are generated; two by phosphoglycerate kinase and two by pyruvate kinase.
Net, two ATPs are produced. If pyruvate kinase is completely deficient, two less ATPs will be produced, and thus the net ATP production will be zero. It is unlikely that the embryo would survive with a complete deficiency of this enzyme.
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