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Energy Transformation

In an energy ...

Question

In an energy recycling process, $X g$ of steam at 100°C becomes water at 100°C which converts $Y$ g of ice at 0°C into water at 100°C. The ratio $X / Y$ will be

\frac{2}{3}

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3

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2

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\frac{1}{3}

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Solution

Use the principle of calorimetry (Heat given by one substance = Heat taken by other substance)
We can write,
$X_{g} (S t e a m a t 100^{0} C) ⟶ X_{l} (W a t e r a t 0^{0} C)$
And also
$Y_{s} (I c e a t 0^{0} C) ⟶ Y_{l} (W a t e r a t 0^{0} C) ⟶ Y_{l} (W a t e r a t 100^{0} C)$
Now we can write
Released energy = $m L θ = 540 X$
Required energy = $m L f + m s Δ T = 80 Y + 100 Y = 180 Y$
According to the principle of calorimetry
$540 X = 180 Y$
$O r, \frac{X}{Y} = \frac{1}{3}$
Hence the required ratio is 1 : 3

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In an energy recycling process, X g of steam at 100°C becomes water at 100°C which converts Y g of ice at 0°C into water at 100°C. The ratio X/Y will be

In an energy recycling process, $X g$ of steam at 100°C becomes water at 100°C which converts $Y$ g of ice at 0°C into water at 100°C. The ratio $X / Y$ will be