In an equilateral ΔABC, Y is a point on AC such that AY : YC = 2 : 3, X and Z are two points on AB such that ZY || XC and XY || BC. If XZ = 6 cm, then XY equals

एक समबाहु ΔABC में, AC पर एक बिंदु Y है जबकि AY : YC = 2 : 3 है और AB पर दो बिन्दु X व Z इस प्रकार हैं कि ZY || XC तथा XY || BC हैं, यदि XZ = 6 cm, तब XY का मान बराबर है

4 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 10 cm
Solution

Suggest Corrections

Similar questions

a x^{2} + 2 h x y + b y^{2} + 2 g x + 2 f y + c = 0

(\frac{b g - h f}{h^{2} - a b}, \frac{a f - g h}{h^{2} - a b})

a x^{2} + 2 h x y + b y^{2} + 2 g x + 2 f y + c = 0

(\sqrt{(\frac{f^{2} - b c}{h^{2} - a b})}, \sqrt{(\frac{g^{2} - a c}{h^{2} - a b})})

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

H_{1}, H_{2}

\frac{H_{1} + H_{2}}{H_{1} . H_{2}} =

H_{1}, H_{2}

2 H . M^{'} . s

a

b

\frac{H_{1} + H_{2}}{H_{1}, H_{2}} =

Join BYJU'S Learning Program