Question

In an equilateral triangle, a perpendicular drawn from one of the vertices to the opposite side bisects the side.

• A. True
• B. False

Answer 1

The correct option is A

True

In$△$ADB and $△$ADC,
AB = AC = a ........(All sides are equal)
AD = AD .............(Common side)
$\angle ADB=\angle ADC={90}^{\circ }$ .... (given)
Now $△ABD\cong △ACD$ according to RHS congruency.
Therefore, BD = DC.