In an equilateral triangle $A B C$ , $A L, B M$ and $C N$ are medians . Forces along $B C$ and $B A$ represented by them will have a resultant represented by

2 ¯ ¯¯¯¯¯¯ ¯ A L

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2 ¯ ¯¯¯¯¯¯¯¯ ¯ B M

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2 ¯ ¯¯¯¯¯¯¯ ¯ C N

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2 ¯ ¯¯¯¯¯¯ ¯ A C

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Solution

The correct option is B $2 ¯ ¯¯¯¯¯¯¯¯ ¯ B M$
$\begin{matrix} H e r e A B C i s a n e q u i l a t e r a l t r i a n g l e i n w h i c h A L, B M a n d C N a r e t h e m e d i a n, p o s e, f o r c e r e p r e s e n t e d b y B C = F a n d f o r c e r e p r e s e n t e d b y B A = F^{'} t h e n t h e r e s u l tan t o f t h e s e f o r c e i s r e p r e s e n t e d b y R w h i c h i s e q u a l t o 2 B M . \end{matrix}$
Hence,
option $(B)$ is correct answer.

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