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A Line through the Center That Bisects the Chord Is Perpendicular to the Chord

In an equilat...

Question

In an equilateral $△$ ABC inscribed in a circle, the perpendicular bisector of BC & the angle bisector of angles B & C meet at the center of the circle.

A

True

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B

False

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Solution

The correct option is A
True

In an equilateral triangle inscribed in a circle, the angle bisectors, altitude & the perpendicular bisectors meet at one point.

And that point is the center of the circle.

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A Line through the Center That Bisects the Chord Is Perpendicular to the Chord

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