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Question

In an equilateral triangle ABC of side 'a', AD is the perpendicular drawn onto side BC. Find ADcot θ in terms of a.

A
a
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B
a2
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C
3a2
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D
3a2
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Solution

The correct option is D 3a2
In ABC, A=B=C=60 since it is equilateral.
Consider ABC,
ADB = 90
ABC = 60
BAD=1806090=30
Similarly, CAD=30
Now ABDACD according to SAS congruency.
Therefore, BD = DC = a2
From Pythagoras theorem,
AD2+BD2=AB2
AD=a2(a2)2
AD=3a2
ADcotθ=ADcot 30=AD×ADBD=3a2×3a2a2
ADcot θ=3a2

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