Question

In an equilateral triangle of side $2\sqrt{3}cm$, the circumradius is

• A. $1$
• B. $\sqrt{3}$
• C. $2$
• D. $2\sqrt{3}$

Answer 1

The correct option is C

$2$

Explanation for the correct option.

Finding the value of circumradius:

The circumradius of an equilateral triangle is $=\frac{side}{\sqrt{3}}$.

Therefore, in the given equilateral triangle, the circumradius will be $=\frac{2\sqrt{3}}{\sqrt{3}}$

$=2cm.$

Hence, option C is correct.