Question

In an equilateral triangle, one angle measures $(3x+30{)}^o$. Find the angles.

Answer 1

In an equilateral triangle all the angles are equal .

$A/Q$ one of the angle measures ${(3x+30)}^{\circ }$

Let $\angle A,\angle B,\angle C$ be the angles.

Then $\angle A=\angle B=\angle C={(3x+30)}^{\circ }$

Also $\angle A+\angle B+\angle C={180}^{\circ }$ (Since sum of all the angles of a $△={180}^{\circ }$)

$\therefore {(3x+30)}^{\circ }+{(3x+30)}^{\circ }+{(3x+30)}^{\circ }={180}^{\circ }\Rightarrow 9x+{90}^{\circ }={180}^{\circ }\Rightarrow 9x={90}^{\circ }\Rightarrow x={10}^{\circ }\angle A=\angle B=\angle C={(3\times 10+30)}^{\circ }={60}^{\circ }$