In an examination a candidate attempts 90% of the questions. Out of these 70% of his answers are correct. Each questions carries 3 marks for the correct answers and -1 mark for the wrong answer. If the marks secured by the candidate is 243, what is the total number of questions?

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Solution

Let total No. of question be x

So, questions attempted = 90x/100 = 9x/10
Correct questions answered = 70% of 9x/10 = 63x/100
therefore, wrong answered = 30% of 9x/10 = 27x/100

Marks for correct answer = 3 * 63x/100 = 189x/100
Marks deducted for wrong answer = 1 * 27x/100 = 27x/100

by question, (189x/100) - (27x/100) = 243
or 162x/100 = 243
hence x = (243*100)/162 = 150 ns.

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