In an examination, a question paper consists of 12 questions divided into two parts i.e., Part I and Part II, containing 5 and 7 questions, respectively. A student is required to attempts 8 questions in all, selecting at least 3 from each part. In how many ways can a student select the questions ?
Here, part I has 5 questions and part II has 7 questions.
Student has to attempt 8 questions selecting at least 3 from each section.
So, Number of ways to select at least 3 from each section and a total of 8 questions. = (3 from part I and 5 from part II) or (4 from part I and 4 from part II) or (4 from part I and 4 from part II) or (5 from part I and 3 from part II)
=(5C3×7C5)+(5C4×7C5)+(5C3×7C3)
=(5×42×1×7×62×1)+(5×7×6×53×2)+(1×75×6×53×2)
=210+175+35=420
Required number of ways = 420.