Question

In an examination, a student must get $60\%$ marks to pass. If a student who gets $120$ marks, fails by $60$ marks. Find the maximum marks.

Answer 1

Given : $\%$ of students who failed in one subject only $=(x-z)\%$

And $\%$ of student who failed in other subject $=(y-z)\%$

$\%$ of student who failed in two subjects $=z\%$

Then, passed students $=[100-\left[\right(x-z)+(y-z)+z]]$

$=100-(x+y-z)$

Given a student get $60\%$ marks to pass and gets $120$ marks

and fail by $60$ marks

Then maximum marks $=\frac{100(120+60)}{60}=\frac{100\times 180}{60}=300$