In an examination hall- students are seated at a distance from each other- to maintain the social distance due to CORONA virus pandemic- Let three students sit at points - - and - whose coordinates are - - - and - - respectively- Based on the above information- answer the following questions-2- What is the midpoint of line segment joining - and -

The midpoint of A and C can be calculated by the midpoint formula as nbsp; (x, y) = 2 + 8/2, 3 + 5/2 = (5, 1) nbsp; Hence the midpoint of AC is (5, 1) n ...

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Standard VI

Mathematics

Collinear Points

In an examina...

Question

In an examination hall, students are seated at a distance from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points 𝐀, 𝐁 and 𝐂 whose coordinates are (𝟐, −𝟑), (𝟒,𝟐), and (𝟖, 𝟓) respectively. Based on the above information, answer the following questions.
2. What is the midpoint of line segment joining 𝐀 and 𝐂?

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Solution

The midpoint of A and C can be calculated by the midpoint formula as
(x, y) = $\frac{2 + 8}{2}, \frac{- 3 + 5}{2}$ = (5, 1)
Hence the midpoint of AC is (5, 1)

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Similar questions

In an examination hall, students are seated at a distance from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points 𝐀, 𝐁 and 𝐂 whose coordinates are (𝟐, −𝟑), (𝟒,𝟐), and (𝟖, 𝟓) respectively. Based on the above information, answer the following questions.
1. What is the distance between 𝐀 and 𝐂?

Q. In an examination hall, students are seated at a distance from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points 𝐀, 𝐁 and 𝐂 whose coordinates are (𝟐, −𝟑), (𝟒,𝟐), and (𝟖, 𝟓) respectively. Based on the above information, answer the following questions.
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Q. In an examination hall, students are seated at a distance of 2 m from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points A, B and C whose coordinates are (4, -3), (7,3), and (8, 5) respectively.
Based on the above information, answer the following questions.
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The midpoint of A and C can be calculated by the midpoint formula as (x, y) = 2+82,−3+52 = (5, 1) Hence the midpoint of AC is (5, 1)

The midpoint of A and C can be calculated by the midpoint formula as
(x, y) = $\frac{2 + 8}{2}, \frac{- 3 + 5}{2}$ = (5, 1)
Hence the midpoint of AC is (5, 1)