In an examination hall, students are seated at a distance from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points 𝐀, 𝐁 and 𝐂 whose coordinates are (𝟐, −𝟑), (𝟒,𝟐), and (𝟖, 𝟓) respectively.

What is the distance between 𝐀 and 𝐂?

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Solution

The distance between A and C:
AC = √[(8 - 2)^2 + (5 + 3)^2]
AC = √(36 +64) = √100
AC = 10 unit

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The distance between A and C: AC = √[(8 - 2)^2 + (5 + 3)^2] AC = √(36 +64) = √100 AC = 10 unit

The distance between A and C:
AC = √[(8 - 2)^2 + (5 + 3)^2]
AC = √(36 +64) = √100
AC = 10 unit